Question
A mixture of 512 ml contains milk and whey protein in
the ratio of 9:7, respectively. When 'p' ml of whey protein and (p + 36) ml of milk are added to this mixture, the ratio of milk to whey protein becomes 4:3. Determine the value of 'p'.Solution
ATQ, Quantity of milk in 512 ml of mixture = (9/16) × 512 = 288 ml Quantity of Whey protein in 512 ml of mixture = (7/16) × 512 = 224 ml According to question; (288 + p + 36)/(224 + p) = 4/3 Or, 972 + 3p = 4p + 896 Or, p = 76
1885 ÷ 64.98 + 7.29 + ? = 69.09
212 + 14 × 23 – 28 × 15 = ? Â
(22² × 8²) ÷ (92.4 ÷ 4.2) =? × 32
567-4824 ÷ 134 =? × 9
Determine the value of 'p' in the expression.
28 ÷ 22p + 1 = 43Â
What will come in place of (?) in the given expression.
(15) ² - (13) ² = ?? = 6.25% of 240 + 25 2 + 17 2 – 16 × 17
35% of 840 + 162 = ? – 25% × 300
(7/5) × (3/4) × (5/9) × (6/7) × 3112 = ?
1024 ÷ 16 + 800 ÷ √64 + ? = 200 * 2