Question
In an 800 ml mixture, 60% is soda, and the remainder is
water. If 96 ml of soda and 128 ml of water are added to this mixture, determine the new ratio of the quantity of soda to the quantity of water in the resulting mixture.Solution
ATQ, Quantity of Soda in 800 ml of mixture = 0.60 × 800 = 480 ml Quantity of water in 800 ml of mixture = 800 - 480 = 320 ml Required ratio = (480 + 96) :(320 + 128) = 576:448 = 9:7
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