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    Question

    In an 800 ml mixture, 60% is soda, and the remainder is

    water. If 96 ml of soda and 128 ml of water are added to this mixture, determine the new ratio of the quantity of soda to the quantity of water in the resulting mixture.
    A 6:7 Correct Answer Incorrect Answer
    B 9:7 Correct Answer Incorrect Answer
    C 9:5 Correct Answer Incorrect Answer
    D 5:7 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Quantity of Soda in 800 ml of mixture = 0.60 ├Ч 800 = 480 ml Quantity of water in 800 ml of mixture = 800 - 480 = 320 ml Required ratio = (480 + 96) :(320 + 128) = 576:448 = 9:7

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