In a container containing 120 liters of pure petrol, 40 liters of petrol are drawn and replaced with the same quantity of diesel. This process is repeated twice more. Determine the approximate quantity of petrol remaining in the container.
ATQ, Quantity of petrol left in the container = y{1 – (a/y)}n Where, y = original quantity of petrol, a = quantity of petrol replaced and n = number of times the process is repeated. Therefore, quantity of petrol left in the container = 120{1 – (40/120)}3 = 35.55 ~ 35.5 litres
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