Question
An 800 ml mixture consists of 60% milk. After adding
βxβ ml of milk and β2xβ ml of honey, the milk-to-honey ratio changes to 9:10. Determine the final quantity of honey in the mixture.Solution
ATQ; Initial quantity of milk = 0.6 Γ 800 = 480 ml Initial quantity of honey = 0.4 Γ 800 = 320 ml According to the question, {(480 + x)/(320 + 2x)} = 9/10 Or, 4800 + 10x = 2880 + 18x Or, 8x = 1920 Or, x = 240 Resultant quantity of honey = 320 + 2x = 320 + 480 = 800 ml
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