Question
48 grams of an alloy 'A' containing only gold, silver and
copper in ratio 1:1:4 respectively is mixed with 30 grams of alloy 'B' which contains only silver and copper in ratio 1:2 respectively. Find the total ratio of silver to copper in the final mixture.Solution
Quantity of silver in 48 gram of alloy 'A' = 48 × (1/6) = 8 gram
Quantity of copper in 48 gram of alloy 'A' = 48 × (4/6) = 32 gram
Quantity of silver in 30 gram of alloy 'B' = 30 × (1/3) = 10 gram
Quantity of copper in 30 gram of alloy 'B' = 30 × (2/3) = 20 gram
Required ratio = (8 + 10) : (32 + 20) = 18 : 52 = 9 : 26
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