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    Question

    48 grams of an alloy 'A' containing only gold, silver and

    copper in ratio 1:1:4 respectively is mixed with 30 grams of alloy 'B' which contains only silver and copper in ratio 1:2 respectively. Find the total ratio of silver to copper in the final mixture.
    A 9 : 26 Correct Answer Incorrect Answer
    B 16 : 9 Correct Answer Incorrect Answer
    C 1 : 2 Correct Answer Incorrect Answer
    D 2 : 1 Correct Answer Incorrect Answer
    E 3 : 8 Correct Answer Incorrect Answer

    Solution

    Quantity of silver in 48 gram of alloy 'A' = 48 ├Ч (1/6) = 8 gram
    Quantity of copper in 48 gram of alloy 'A' = 48 ├Ч (4/6) = 32 gram
    Quantity of silver in 30 gram of alloy 'B' = 30 ├Ч (1/3) = 10 gram
    Quantity of copper in 30 gram of alloy 'B' = 30 ├Ч (2/3) = 20 gram
    Required ratio = (8 + 10) : (32 + 20) = 18 : 52 = 9 : 26

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