Question
βxβ litres of mixture βAβ contains milk and
water, only in the ratio of 6:5, respectively. 90 litres of mixture βBβ contains 25% more water than milk in it. If both the given mixtures are mixed together, then ratio of quantity of milk to that of water in the resultant mixture becomes 10:11, respectively. Find the value of βxβ.Solution
Quantity of milk in mixture βAβ = (6x/11) litres Quantity of water in mixture βAβ = (5x/11) litres Let quantity of milk in mixture βBβ = β2aβ litres Quantity of water in mixture βBβ = 1.25 Γ 2a = β2.5aβ litres So, 2a + 2.5a = 90 Or, 4.5a = 90 Or, a = 20 So, quantity of milk in mixture βBβ = 2 Γ 20 = 40 litres Quantity of water in mixture βBβ = 2.5 Γ 20 = 50 litres ATQ, {(6x/11) + 40)}/{(5x/11) + 50)} = (10/11) Or, (6x + 440)/(5x + 550) = 10/11 Or, 66x + 4840 = 50x + 5500 Or, 66x β 50x = 5500 - 4840 Or, 11x = 660 Or, x = 60
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