Question
βxβ litres of mixture βAβ contains milk and
water, only in the ratio of 6:5, respectively. 90 litres of mixture βBβ contains 25% more water than milk in it. If both the given mixtures are mixed together, then ratio of quantity of milk to that of water in the resultant mixture becomes 10:11, respectively. Find the value of βxβ.Solution
Mixture A (x litres): Milk = (6/11)x Water = (5/11)x Mixture B (90 litres): Milk = 40 Water = 50 Equation: ( (6/11)x + 40 ) / ( (5/11)x + 50 ) = 10 / 11 Cross multiply: 11((6/11)x + 40) = 10((5/11)x + 50) 6x + 440 = (50/11)x + 500 6x β (50/11)x = 60 (16/11)x = 60 x = (60 Γ 11) / 16 x = 41.25
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