In a mixture, nitrogen and HCL are present in a 4:1

Solution

Let the quantity of the nitrogen initially = ‘4a’ litres And, the quantity of the HCL initially = ‘a’ litres Quantity of the nitrogen that is taken out = 4a × 25% = a litres Quantity of the HCL that is taken out = a × 25% = 0.25a litres According to the question, (4a – a):(a – 0.25a + X) = 1:4 12a = 0.75a + X X = 11.25a…………………….(1) Again, (4a – a + Y):(a – 0.25a + X) = 3:2 (3a + Y):(0.75a + 11.25a) = 3:2 (From equation 1) 2(3a + Y) = 3 × 12 3a + Y = 18a Y = 15x Required percentage = (11.25a/15a) × 100 = 75%