Question
A 120 litres solution of alcohol and water contains 30%
alcohol. When Q litres of alcohol and (Q - 4) litres of water are added to the solution, the quantity of alcohol becomes 3/7 of the total solution. What is the value of (Q - 13)?Solution
ATQ,
Quantity of alcohol in the initial solution = 0.30 × 120 = 36 litres Quantity of water in the initial solution = 120 - 36 = 84 litres ATQ: 36 + Q = (3/7) × (120 + Q + Q - 4) → 36 + Q = (3/7) × (120 + 2Q - 4) → 36 + Q = (3/7) × (116 + 2Q) → 7(36 + Q) = 3(116 + 2Q) → 252 + 7Q = 348 + 6Q → Q = 96 Required value = Q - 13 = 96 - 13 = 83
564.932 + 849.029 – 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of ₹60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to ₹75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 ÷ 40.48 × 10.12 = ? × 2.16
(124.901) × (11.93) + 219.95 = ? + 114.891 × 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
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