Question
The batting average of 40 innings of a cricket player is
50 runs. His highest score exceeds his lowest by 172 runs. If the two are excluded, the average of the remaining 38 innings is 48runs. Find the highest score of the player?Solution
Let the highest score be x Then, lowest score = x-172 Then, (50 × 40) - [x + (x - 172)] = 38 × 48 2x = 2000 + 172 - 1824 2x = 348 ∴ x = 174
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