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    Question

    The batting average of 40 innings of a cricket player is

    50 runs. His highest score exceeds his lowest by 172 runs. If the two are excluded, the average of the remaining 38 innings is 48runs. Find the highest score of the player?
    A 176 Correct Answer Incorrect Answer
    B 175 Correct Answer Incorrect Answer
    C 174 Correct Answer Incorrect Answer
    D 184 Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    Let the highest score be x Then, lowest score = x-172 Then, (50 × 40) - [x + (x - 172)] = 38 × 48 2x = 2000 + 172 - 1824 2x = 348 ∴ x = 174

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