Question
Average of four consecutive prime numbers T1, T2, T3,
and T4 is (17 + x). If the average of T1 and T2 is (13 + x) and the average of T3 and T4 is (13 + 3x), then find T4.Solution
ATQ, Sum of T1, T2, T3, and T4 = (17 + x) × 4 = 68 + 4x Sum of T1 and T2 = (13 + x) × 2 = 26 + 2x Sum of T3 and T4 = (13 + 3x) × 2 = 26 + 6x Now, setting the equations equal: 26 + 2x + 26 + 6x = 68 + 4x Or, x = 4 Sum of T3 and T4 = 26 + 6 × 4 = 50 T3, T4 = 23, 29 Answer: T4 = 29
More Average Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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