Question
Average of four consecutive prime numbers T1, T2, T3,
and T4 is (17 + x). If the average of T1 and T2 is (13 + x) and the average of T3 and T4 is (13 + 3x), then find T4.Solution
ATQ, Sum of T1, T2, T3, and T4 = (17 + x) × 4 = 68 + 4x Sum of T1 and T2 = (13 + x) × 2 = 26 + 2x Sum of T3 and T4 = (13 + 3x) × 2 = 26 + 6x Now, setting the equations equal: 26 + 2x + 26 + 6x = 68 + 4x Or, x = 4 Sum of T3 and T4 = 26 + 6 × 4 = 50 T3, T4 = 23, 29 Answer: T4 = 29
Express 7/16 as a decimal correct to three decimal places.
2.666 …+ 2.77… in fraction form is:
Calculate: 0.75 × 0.4 + 2.5 ÷ 0.5 − 0.36
Evaluate: 3.75 × 0.4 + 7.2 ÷ 0.6
Evaluate: 2.4 × 1.25 + 6.5 ÷ 0.5
Calculate: 7.2 ÷ 0.3 + 1.25 × 0.4 − 0.18
Evaluate: 3.25 + 4.08 − 1.6 × 1.5
Simplify:
0.36 ÷ 0.06 − 1.25 × (4/5) + 7/8
A man distributed some candies to his three sons A, B and C. A, being the eldest got two times the number of candies that C got while A and B together...
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