Question
A mixture contains 96 ml of milk and 48 ml of water. If
36 ml of the mixture is replaced with 24 ml of water, then find the ratio of quantity of milk to that of water in the resultant mixture.Solution
Initial ratio of quantity of milk to that of water = 96:48 = 2:1 Quantity of milk withdrawn = 36 × (2/3) = 24 ml Final quantity of milk = 96 – 24 = 72 ml Quantity of water withdrawn = 36 × (1/3) = 12 ml Final quantity of water = 48 – 12 + 24 = 60 ml Required ratio = 72:60 = 6:5
Find the value of the given expression.
2 × (sin 30° + tan 45°)
Find the value of the given expression.
5 × (cos 60°)
(tan 5x - tan 3x - tan 2x) = ?
Find the value of the given expression.
2 × (sec 60° – sin 30°)

- If sec 2P = sin² 60⁰ + sec 60⁰ - cos² 30⁰, then determine the value of (√3tan P + cot² P)
Find the simplified value of:

If sinθ = 5/13 for an acute angle θ, find:
(a) cosθ, (b) tan(90° − θ).