Question
A 40-litre mixture of milk and water contains them in the ratio 7 : 3. How many litres of water must be added so that the ratio of milk to water becomes 7 : 5?
Solution
Total mixture = 40 litres Milk : water = 7 : 3 Milk = (7/10) × 40 = 28 litres Water initially = 40 − 28 = 12 litres Let x litres of water be added. New water = 12 + x, milk remains 28 Required ratio: 28 : (12 + x) = 7 : 5 28/(12 + x) = 7/5 Cross-multiply: 28 × 5 = 7(12 + x) 140 = 84 + 7x 7x = 56 → x = 8 Answer = 8 litres
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