Question
A container has 40 liters of a mixture of milk and
water, where the ratio of milk to water is 5:3. If 8 liters of the mixture is removed and replaced with pure water, what is the new ratio of milk to water?Solution
Milk in the mixture = (5/8) × 40 = 25 liters Water in the mixture = (3/8) × 40 = 15 liters When 8 liters of the mixture is removed, the quantity of milk removed = (5/8) × 8 = 5 liters The quantity of water removed = (3/8) × 8 = 3 liters Remaining milk = 25 - 5 = 20 liters Remaining water = 15 - 3 = 12 liters Now, 8 liters of water is added: New water quantity = 12 + 8 = 20 liters New ratio of milk to water = 20:20 = 1:1 Correct Option: a) 1:1
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