Question
Mixture 'A' consists of milk and water in a ratio of
7:8, while mixture 'B' contains milk and water in a ratio of 3:2. When these two mixtures are combined, the quantity of mixture 'A' is taken to be twice that of mixture 'B'. Determine the percentage of milk in the resulting mixture.Solution
Let 'C' denote the final mixture. Let the quantity of 'A' which is mixed in 'C' be '30x' ml So, the quantity of 'B' which is mixed in 'C' = '15x' ml Quantity of milk in 30x ml of 'A' = 30x X (7/15) = '14x' ml Quantity of milk in 15x ml of 'B' = 15x X (3/5) = '9x' ml So, total quantity of milk in the final mixture = 14x + 9x = '23x' ml Total quantity of 'C' = 30x + 15x = 45x ml Therefore, required percentage = (23x/45x) X 100 =Â 51(1/9)%
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