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Let 'C' denote the final mixture. Let the quantity of 'A' which is mixed in 'C' be '30x' ml So, the quantity of 'B' which is mixed in 'C' = '15x' ml Quantity of milk in 30x ml of 'A' = 30x X (7/15) = '14x' ml Quantity of milk in 15x ml of 'B' = 15x X (3/5) = '9x' ml So, total quantity of milk in the final mixture = 14x + 9x = '23x' ml Total quantity of 'C' = 30x + 15x = 45x ml Therefore, required percentage = (23x/45x) X 100 = 51(1/9)%
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