Question
One alloy of steel contains 74% Iron and 26% carbon.
Another alloy contains 81% Iron and 12% carbon. Later, they are mixed, so that the mixture contains 20% of carbon. What percent of Iron will it contain?Solution
The alloy should be mix in the ratio of 4:3 Now,
Difference of 81-74 = 7 7 is divided in the ratio of 4:3 7 × `3/7` = 3% So required iron% = 74+3 = 77%
564.932 + 849.029 β 425.08 = 612.095 + ?
999.99 + 99.99 + 99= ?
A sum of βΉ60,000 is invested at a compound interest rate of 'x%' per annum, compounded annually, and grows to βΉ75,264 in 2 ye...
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...
³√? × 33.97 + 59.99 × 28.9 – 48.98 × 21.42 = 1085.344
1279.98 Γ· 40.48 Γ 10.12 = ? Γ 2.16
(124.901) Γ (11.93) + 219.95 = ? + 114.891 Γ 13.90
What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)...