Question
One alloy of steel contains 74% Iron and 26% carbon.
Another alloy contains 81% Iron and 12% carbon. Later, they are mixed, so that the mixture contains 20% of carbon. What percent of Iron will it contain?Solution
The alloy should be mix in the ratio of 4:3 Now, 
Difference of 81-74 = 7 7 is divided in the ratio of 4:3 7 × `3/7` = 3% So required iron% = 74+3 = 77%
More Mixture Questions
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?
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