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    Question

    One alloy of steel contains 74% Iron and 26% carbon.

    Another alloy contains 81% Iron and 12% carbon. Later, they are mixed, so that the mixture contains 20% of carbon. What percent of Iron will it contain?
    A 87% Correct Answer Incorrect Answer
    B 65% Correct Answer Incorrect Answer
    C 77% Correct Answer Incorrect Answer
    D 53% Correct Answer Incorrect Answer
    E None of these Correct Answer Incorrect Answer

    Solution

    The alloy should be mix in the ratio of 4:3 Now, Difference of 81-74 = 7 7 is divided in the ratio of 4:3 7 × `3/7` = 3% So required iron% = 74+3 = 77%

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