Question
Quantity of water in a 360 litres mixture (alcohol +
water) is 20 litres less than the quantity of alcohol in it. Find the quantity of water to be mixed so that the quantity of alcohol in the mixture becomes 50% of the whole mixture.Solution
Quantity of water in the mixture = (360 β 20)/2 = 170 litres So, Quantity of alcohol in the mixture = (360 β 170) = 190 litres Total quantity of the mixture = 190 x (100/50) = 380 litres Therefore, quantity of water to be mixed = 380 β 360 = 20 litres
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