Question
In a 180-liter mixture, there is a ratio of 11:7 between
Milk and Glucose. How much additional Glucose should be added to the mixture so that the quantity of glucose becomes 50% of the resultant mixture?Solution
ATQ, Quantity of Glucose in the initial mixture = 180 × (7/18) = 70 liters Quantity of Milk in the initial mixture = 180 × (11/18) = 110 liters Since, we’re not adding Milk, 110 litres of Milk will represent 50% of the new mixture. So, total quantity of resultant mixture = 110 ÷ 0.5 = 220 liters Quantity of Glucose to be added = 220 – 180 = 40 liters
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
I:Â x2Â - 33x + 242 = 0
II:Â y2Â - 4y - 77 = 0
I. x² - 208 = 233
II. y² + 47 - 371 = 0
I. 2b2 - 37b + 143 = 0
II. 2a2 + 15a - 143 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: x² - 45x + 450 = 0
Equation 2: y² - 48y + 540 = 0�...
I). p2 + 22p + 72 = 0,
II). q2 - 24q + 128 = 0
I. √(74x-250 )– x=15
II. √(3y²-37y+18)+ 2y=18
I. 3y² - 20y + 25 = 0
II. 3x² - 8x + 5 = 0
I. 2y2 - 15y + 18 = 0
II. 2x2 + 9x - 18 = 0
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 103x² - 470x + 367 = 0
Equation 2: 107y² - 504y + 397 = 0
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