Question
The diluted wine contains only 8 liters of wine, and the
rest is water. A new mixture whose concentration is 30%, is to be formed by replacing wine. How many liters of mixture shall be replaced with pure wine if there were initially 32 liters of water in the mixture?Solution
Wine: Water 8lt: 32lt. 1:4 20%:80% (original ratio) 30%:70% (required ratio) In this case, the percentage of water being reduced when the mixture is being replaced with wine. So, the ratio of left quantity to the initial quantity = 7:8 Let the replaced amount of water with pure wine be X lt. As per the question (40-X)/40 = 7/8 320-8X=280 40 = 8X 5 = X So, 5 lt. Of pure wine replaced water in the mixture
What will come in place of the question mark (?) in the following series?
32, ?, 30, 46, 28, 44
What will come in place of the question mark (?) in the following series?
112, 123, 144, 169, 190, ?
What will come in place of (?) Question mark in the given number series.
28, 29, 38, 63, 112, 193, ?
53 × 38 + 32 × âˆ›54872 = ?
45Â Â Â Â 45.5Â Â Â Â Â Â 47 Â Â Â Â Â Â 49.5Â Â Â Â Â Â 53 Â Â Â Â Â Â ?
...- What will come in place of the question mark (?) in the following series?
?, 162, 54, 18, 9, 3 58   83   133   ?    308    433
8Â Â Â 8Â Â Â 12Â Â Â 24Â Â Â Â 60Â Â Â Â Â ?
84, 97, ?, 162, 214, 279
24, 35, 48, 65, 84, 107
