Question
A milkman has milk containing 30% water. How many litres
of pure milk must he add to 20 litres of this mixture so that the water content becomes 20%?Solution
In 20 L of mixture, water = 30% of 20 = 6 L So milk = 14 L Let x L of pure milk be added. New total volume = 20 + x Water remains = 6 L We want water to be 20%: 6 = 20% of (20 + x) 6 = 0.20(20 + x) 6 = 4 + 0.2x 0.2x = 2 x = 2 / 0.2 = 10 L Answer: Add 10 litres of pure milk.
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