Question
In a mixture of milk and water, the quantity of water is
50% more than the quantity of milk. If 16 liters of water is mixed into it, then the quantity of milk will be 34% less than the quantity of water. Find out the difference between the initial quantity of milk and water in the mixture (in liters).Solution
In a mixture of milk and water, the quantity of water is 50% more than the quantity of milk. Letβs assume the initial quantity of milk is 2y. quantity of water initially = (100+50)% of 2y = 150% of 2y = 3y If 16 liters of water is mixed into it, then the quantity of milk will be 34% less than the quantity of water. 2y/(3y+16) = 66/100 y/(3y+16) = 33/100 100y = 99y+528 y = 528 Difference between the initial quantity of milk and water in the mixture = (3y-2y) = y = 528
Evaluate:
β729 + β49 - β16 + 1/β64
Simplify:

(1/5)(40% of 800 β 120) = ? Γ 5
2/5 of 3/4 of 7/9 of 7200 = ?
`sqrt(5476)` + 40% of 1640 = ? `xx` 4 - 2020
? = (22% of 25% of 60% of 3000) + 21
Determine the simplified value of the given mathematical expression.
(342 β 20% of 5280) = ? Γ· 3
β157464 =?