Question
A mixture (acid + water) contains acid and water in the
ratio of 11:6, respectively. If 68 litres of the mixture is replaced with 40 litres of water, then quantity of acid in the final mixture becomes 20 litres more than that of water. Find the initial quantity of the mixture.Solution
Let the quantity of acid and water in the initial mixture be ‘11x’ litres and ‘6x’ litres, respectively Quantity of acid in 68 litres of the mixture
= 68 × (11/17) = 44 litres Quantity of water in 68 litres of the mixture
= 68 − 44 = 24 litres According to the question, (11x − 44) = (6x − 24 + 40) + 20 Or, 11x − 6x = 44 + 24 + 20 Or, 5x = 88 Or, x = 16 Initial quantity of the mixture
= 17x = 17 × 16 = 272 litres
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