Question
A solution contains acid and water in the ratio of 3:11.
If 10 litres of acid is added to the solution, the ratio of acid to water becomes 1:2. What was the initial amount of acid in the solution?Solution
Let the initial quantity of acid and water be β3xβ and β11xβ litres, respectively. So, (3x + 10)/11x = 1/2 6x + 20 = 11x 5x = 20, x = 4 So, the initial amount of acid = 3x = 12 litres
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