Question
Two mixtures (milk and water) 'A' and 'B' contains
quantities of milk and water in ratio of 3:2 and 5:3, respectively. If 40 ml from 'A' and 32 ml from 'B' are mixed to form a new mixture, then find the percentage of water in the new mixture.Solution
Quantity of water in 40 ml of mixture 'A' = 40 × (2/5) = 16 ml
Quantity of water in 32 ml of mixture 'B' = 32 × (3/8) = 12 ml
Total quantity of final mixture = (40 + 32) = 72 ml
Required percentage = ((16 + 12) ÷ 72) × 100 = 28/72 × 100 = 38.89% ≈ 39%
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