Question
200 litres of mixture (milk + water) contains 50% milk.
When 'm' litres of milk and (m - 10) litres of water are added, the ratio of milk to water in the final mixture becomes 3:4. Find the value of '2m'.Solution
ATQ,
Initial quantity of milk = 0.5 × 200 = 100 litres Initial quantity of water = 200 - 100 = 100 litres ATQ: (100 + m) : (100 + m - 10) = 3:4 Or, 4 × (100 + m) = 3 × (90 + m) Or, 400 + 4m = 270 + 3m Or, m = 130 Required value = '2m' = 2 × 130 = 260
Statements: E > O, S < Z, O ≤ S
Conclusions:
I. E < S
II. O < Z
Statement: W>Y<X<Z=U>S; W<T ≥V
I. Y<T
II. X > V
Statements: L ≥ O = J ≥ I ≤ V; C = T ≤ J
Conclusion: I. C < L II. C = L
Statements: P < Q ≤ R ≤ S; P > T = V ≥ X; S ≤ W = Y < U
Conclusions:
I. U > R
II. W > X
III. Q < Y
Statements: W ≤ B = F; H > T; H < U < F; W ≤ X < S
Conclusions:
I. W < U
II. T < B
III. X > H
Statements: A < B ≤ C, A > E, F ≤ B < D
Conclusions:
I. D > A
II. E < B
III. C > E
IV. D > C
Statements: W < R = T < Y = S = U ≥ V ≥ H = X
Conclusions:
I. S ≥ X
II. U > T
III. W < Y
Statements: B ≥ U > P = E ≥ X; X > K > N ≥ J
Conclusions: I. N < P   II. J ≤ X
Statements:Q = S > T > Z; T > Y = H < I
Conclusions: I. Z > H II. I > Z
Statements: X @ Y $ Z & U, Z @ V
Conclusions: I. V # X II. V $ X
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