Question
Two mixtures A and B have milk:water ratios 3:2 and 4:5.
They are poured together to get 0.732 litres of mixture where milk:water in the result is 31:30. What was the initial quantity of mixture B?Solution
ATQ, In A: milk = 3x ml, water = 2x ml. In B: milk = 4y ml, water = 5y ml. Total = 0.732 L = 732 ml Milk in 732 ml = (31/61) × 732 = 372 ml Water in 732 ml = 732 – 372 = 360 ml Equations: 3x + 4y = 372 2x + 5y = 360 Solving ⇒ x = 60, y = 48 Quantity of mixture B = y × (4+5) = 48 × 9 = 432 ml
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