Question

    Four circles of equal radii are described about the four

    corners of a square so that each touches two of the other circles. If each side of the square is 140 cm then area of the space enclosed between the circumference of the circle is (take π = 22/7)
    A 4200 cm^2 Correct Answer Incorrect Answer
    B 2100 cm^2 Correct Answer Incorrect Answer
    C 7000 cm^2 Correct Answer Incorrect Answer
    D 2800 cm^2 Correct Answer Incorrect Answer

    Solution

    Side of the square a = 140 cm Radius of the circle r = 140/2 = 70 cm Area of 4 quadrant = area of 1 circle As we know, Area of the square = a2 Area of the circle = πr2 Area of the space enclosed between the circumference of the circle = a2 – πr2 ⇒ 140 × 140 – (22/7) × 70 × 70 ⇒ 19600 – 15400 ⇒ 4200 cm^2

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