Question
Four circles of equal radii are described about the four corners of a square so that each touches two of the other circles. If each side of the square is 140 cm then area of the space enclosed between the circumference of the circle is (take π = 22/7)
More Mensuration Questions
- If the height of a cylinder becomes double and radius decreases by 50%, then what is the percentage change in its volume?
- A solid hemisphere of diameter 8 cm is placed over a cube whose side is 7 cm. Calculate the total surface area of the combined structure. [Use π = 3]
- The ratio of the curved surface area and the total surface area of a cylinder is 5:7, respectively. Find the ratio of the height and radius of the cylinder...
- The length of a cuboid increases by 5%, its breadth decreases by 10% and its height increases by 25%. Find the percentage change in the volume.
- If x1 and x2 are the roots of the equation 2x2 + 3x – 9 = 0, then the equation which has the roots 1/x1 and1/x2 is:
- The angle of elevation of the top of an unfinished tower at a point distant 78 m from its base is 30°. How much higher must the tower be raised (in m) so t...
- The volume and height of a cylinder are 4224 cm3 and 21 cm. Find the radius of the cylinder.
- The side of a square is increased by 40%. Find the percentage change in its area?
- A polygon has 40 diagonals, the number of sides of the polygon is?
- Angle bisectors of Q and R meet at point S, inside the triangle PQR. If angle QSR = 128˚ , then the measure of angle P is:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)
Side of the square a = 140 cm Radius of the circle r = 140/2 = 70 cm Area of 4 quadrant = area of 1 circle As we know, Area of the square = a2 Area of the circle = πr2 Area of the space enclosed between the circumference of the circle = a2 – πr2 ⇒ 140 × 140 – (22/7) × 70 × 70 ⇒ 19600 – 15400 ⇒ 4200 cm^2