A jar contains 160 litres mixture of juice and water, where the quantity of juice is 20 litres more than that of water. If 20% of the mixture is taken out and 28 litres of juice and 69 litres of water are added to the jar, then the quantity of juice is what percentage of the quantity of water in the jar?

Let the quantity of water in the mixture = ‘x’ litres Then, quantity of juice in the mixture = (x + 20) litres So, x + x + 20 = 160 Or, 2x = 160 – 20 = 140 Or, x = 140/2 = 70 So, quantity of water in the mixture = 70 litres And, quantity of juice in the mixture = 70 + 20 = 90 litres Quantity of juice in 20% of mixture = 90 × 0.20 = 18 litres Quantity of water in 20% of mixture = 70 × 0.20 = 14 litres So, quantity of juice in the jar = (90 – 18) + 28 = 100 litres Quantity of water in the jar = (70 – 14) + 69 = 125 litres So, required percentage = (100/125) × 100 = 80% Hence, the correct answer is B.