Question
A milkman has 40 litres of milk containing 10% water.
How much pure water must he add so that water becomes 25% of the final mixture?Solution
Initial total = 40 L Water initially = 10% of 40 = 4 L Milk = 36 L Let x litres of water be added. Final water = 4 + x Final total = 40 + x Given water = 25% of total: (4 + x)/(40 + x) = 0.25 4 + x = 0.25(40 + x) 4 + x = 10 + 0.25x x − 0.25x = 10 − 4 0.75x = 6 x = 6 / 0.75 = 8 L Answer: Add 8 litres of water.
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