Question
Container 'P' has 180 litres of a water–soda mixture
in the ratio 3:2. 25% of this mixture is shifted to container 'Q', which already contains 19 litres of water. Then 50% of the mixture from 'Q' is poured back into the remaining mixture of 'P'. Find the quantity of soda in the final mixture.Solution
ATQ,
Initial quantity of water in container 'P' = 180 × (3/5) = 108 litres Initial quantity of soda in container 'P' = 180 − 108 = 72 litres Quantity of water moved to container 'Q' = 0.25 × 108 = 27 litres Quantity of soda moved to container 'Q' = 0.25 × 72 = 18 litres Quantity of water in container 'Q' = 27 + 19 = 46 litres Quantity of soda in container 'Q' = 18 litres ATQ, Quantity of soda in resultant mixture = (remaining soda in 'P') + (soda returned from 'Q') = (72 × 0.75) + (0.5 × 18) = 54 + 9 = 63 litres
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