Question
Container 'P' has 180 litres of a waterâsoda mixture
in the ratio 3:2. 25% of this mixture is shifted to container 'Q', which already contains 19 litres of water. Then 50% of the mixture from 'Q' is poured back into the remaining mixture of 'P'. Find the quantity of soda in the final mixture.Solution
ATQ,
Initial quantity of water in container 'P' = 180 Ă (3/5) = 108 litres Initial quantity of soda in container 'P' = 180 â 108 = 72 litres Quantity of water moved to container 'Q' = 0.25 Ă 108 = 27 litres Quantity of soda moved to container 'Q' = 0.25 Ă 72 = 18 litres Quantity of water in container 'Q' = 27 + 19 = 46 litres Quantity of soda in container 'Q' = 18 litres ATQ, Quantity of soda in resultant mixture = (remaining soda in 'P') + (soda returned from 'Q') = (72 Ă 0.75) + (0.5 Ă 18) = 54 + 9 = 63 litres
Select the figure from among the given options that can replace the question mark (?) in the following series.
Select the figure from among the given options that can replace the question mark (?) in the following series.
Select the figure from among the given options that can replace the question mark in the given series.
Each of the following questions consists of two sets of figures. Figures A, B, C and D constitute the Problem Set while figures (1), (2), (3) and (4) c...
Select the figure which will come next in the following figure series.
Select the figure from the options that can replace the question mark (?) in the following series.
Select the figure from among the given options that can replace the question mark (?) in the following series.
Find the question mark ? figure from answer figure.
Select the figure that will come next in the following figure series.
2 + 5 = 36
7 + 6 = 98
6 + 4 = 62
4 + 9 = ?
Relevant for Exams:
