Question
A milk seller has a 90-litre mixture of milk and water,
where water makes up 45% of the total volume. He wants to adjust the mixture so that the amounts of milk and water become equal. However, instead of adding milk, he mistakenly adds the same amount of water. What will be the final ratio of water to milk in the mixture?Solution
ATQ;
Present quantity of water in the mixture = 90 X 0.45 = 40.5 litres
Present quantity of milk in the mixture = 90 - 40.5 = 49.5 litres
Quantity of milk to be added = 49.5 - 40.5 = 9 litres
Required ratio = (40.5 + 9):49.5 = 1:1
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Derision
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