Question
A 150 ml solution consists of alcohol and water in a
ratio of 2:3. A portion of this mixture is removed, containing 18 ml of water, and then 6 ml of alcohol is added back to the remaining solution. Determine the new ratio of alcohol to water in the final mixture.Solution
Initial quantity of alcohol in the mixture = (2/5) Ă— 150 = 60 ml
So, the initial quantity of water = 150 – 60 = 90 ml
The percentage of water removed = (18/90) Ă— 100 = 20%
Which means 20% of the mixture is removed.
So, the new quantity of alcohol in the mixture = 0.8 Ă— 60 = 48 ml
New quantity of water = 90 – 18 = 72 ml
ATQ, Final quantity of alcohol in the mixture = 48 + 6 = 54 ml
So, the required ratio = 54:72 = 3:4
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