Question
A 150 ml solution consists of alcohol and water in a
ratio of 2:3. A portion of this mixture is removed, containing 18 ml of water, and then 6 ml of alcohol is added back to the remaining solution. Determine the new ratio of alcohol to water in the final mixture.Solution
Initial quantity of alcohol in the mixture = (2/5) × 150 = 60 ml
So, the initial quantity of water = 150 – 60 = 90 ml
The percentage of water removed = (18/90) × 100 = 20%
Which means 20% of the mixture is removed.
So, the new quantity of alcohol in the mixture = 0.8 × 60 = 48 ml
New quantity of water = 90 – 18 = 72 ml
ATQ, Final quantity of alcohol in the mixture = 48 + 6 = 54 ml
So, the required ratio = 54:72 = 3:4
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5, 15, 35, 75, 155, ? 21, 37, 73, 137, ?, 381
What value should come in the place of (?) in the following number series?
14, 43, 132, 401, 1210, ?, 10928
- What will come in place of the question mark (?) in the following series?
10, 17, 26, 37, 50, ? What will come in place of the question mark (?) in the following series?
1528, 1416, 1204, ?, 480, -32
What will come in place of the question mark (?) in the following series?
562, 56...
4, 4, 12, 60, ?, 3780
1, 7, 25, 61, ?
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What will come in place of the question mark (?) in the following series?
2, 5, 14, 41, 122, 365, ?
