Question
300 ml of mixture contains milk and water in the ratio
of 16:x respectively. If 50 ml of water and 60 ml of milk is added into it then ratio of milk to water in the resulting mixture will be 2:1. Find the value of ‘x’.Solution
Quantity of milk in 300 ml of mixture = 300 × 16/(16 + x) Quantity of water in 300 ml of mixture = 300 × x/(x + 16) According to question; {4800/(16 + x) + 60}/{300x/(x + 16) + 50} = 2/1 Or, 4800/(16 + x) + 60 = 600x/(x + 16) + 100 Or, (4800 – 600x)/(x + 16) = 40 Or, 4800 – 600x = 40x + 640 Or, 640x = 4160 Or, x = 6.5
Simplify:
6x + 8y - [(12x + 6y) - (4x + 3y) + 2y] - 4xIf 9x2 + 16y2 = 24xy, then find the ratio of ‘x’ and ‘y’, respectively.
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