Question
In the mixture of 84 liters, the ratio of milk and water
is 5: 7. If this ratio is changed to 3: 5, then tell the amount of excess water (in liters) mixed in the mixture.Solution
Total quantity of mixture = 84 liters Quantity of milk in the mixture = 5/12 x 84 = 35 liters Quantity of water in the mixture = 84-35 = 49 liters Let the quantity of water added to the mixture be x liters. 35/ (49 + x) = 3/5 35 x 5 = (49 + x) x 3 175=147 + 3x 3x = 175-147 3x = 28 x = 28/3 x = 9.33 liters.
More Mixture Questions
12.5% of (100 + ?) = 40
2/9 of 5/8 of 3/25 of ? = 40
24 × √? + 4008 ÷ 24 = 40% of 200 + 327
7(1/2) – 3(5/6) = ? − 2(7/12)
280 ÷ 14 + 11 × 12 – 15 × 6 = ?
1550 ÷ 62 + 54.6 x 36 = (? x 10) + (28.5 x 40)
25% of 1000 + 10% of 150 – 22 × ? = 45
√ 729 × 5 – 220 % of 15 + ? = 120% of 160
What will come in the place of question mark (?) in the given expression?
(40% of ? × 43 ) – 232 = 751
180 % of 45 + √144 × 8 = ?2 + 80 % of 70
