Question
The container has 45 liters of mixture of alcohol and
water in the ratio of 4:1. If 20 liters of mixture is replaced by water, then what is the ratio of the quantity of alcohol to water in the final mixture?Solution
Alcohol in the container = (4/5) × 45 = 36 liters Water in container = 45 - 36 = 9 liters Alcohol in 20 liters of mixture = 20 × (4/5) = 16 liters Water in 20 liters of mixture = 20 – 26 = 4 liters Required ratio = (36 – 16) : (9 – 4 + 20) = 4:5
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