Question
A mixture contains 70 litres of milk and the rest water
such that the ratio of the quantity of milk to that of water in the mixture is 7:3. How many litres of water should be added to the mixture such that milk constitutes 35% of the resultant mixture?Solution
ATQ, Total quantity of initial mixture = 70 × (10/7) = 100 litres Since the quantity of milk remains unchanged, therefore Total quantity of resultant mixture = (70/0.35) = 200 litres Therefore, the quantity of water added = 200 - 100 = 100 litres
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?