Question
A vessel contains mixture in which 25% is water and rest
is milk. If 40 liters more water added in vessel, then quantity of water becomes 40% of mixture. Find the quantity of milk in the vessel?Solution
Let total mixture in vessel be Q liters. Initial quantity of water in vessel = 0.25Q And, quantity of milk in vessel = 0.75Q (0.25Q + 40)/0.75Q = 40/60 15Q + 2400 = 30Q 15Q = 2400 Q = 160 lit Quantity of milk in vessel = 160 × 75/100 = 120 lit
15.99% of 549.99 ÷ 11.17 = ? ÷ 20.15
74.91% of 639.95 – 599.98% of 45 + 119.987 = ?
(4.88 × 5.76)2 - ?2 = 39.89 × 19.86
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
(1800.23 ÷ 29.98) + (816.32 ÷ 23.9) + 1634.11 = ?
1449.98 ÷ 50.48 × 10.12 = ? × 2.16
36.05 × 5.02 + 12.052 = ? + 9.09 × 4.04Â
(31.9)3 + (34.021)² - (16.11)3 - (42.98)² = ?