Question
Quantity of water in a 420 litres mixture (alcohol +
water) is 30 litres less than the quantity of alcohol in it. Find the quantity of water to be mixed so that the quantity of alcohol in the mixture becomes 45% of the whole mixture.Solution
Quantity of water in the mixture = (420 β 30)/2 = 195 litres So, Quantity of alcohol in the mixture = (420 β 195) = 225 litres Total quantity of the mixture = 225 x (100/45) = 500 litres Therefore, quantity of water to be mixed = 500 β 420 = 80 litres
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