A mixture (cola + water) contains cola and water in the ratio of 3:2. If 40 liters of the mixture is replaced with 10 liters of water, then the quantity of cola in the final mixture becomes 18 liters more than that of water. Find the initial quantity of the mixture.
ATQ, Let the quantity of cola and water in the initial mixture be '3u' liters and '2u' liters, respectively. Quantity of cola in 40 liters of the mixture = 40 x (3/5) = 24 liters. Quantity of water in 40 liters of the mixture = 40 - 24 = 16 liters. According to the question, (3u - 24) = (2u - 16 + 10) + 18 Or, 3u - 2u = 24 - 16 + 10 + 18 Or, u = 36 Initial quantity of the mixture = 5u = 5 x 36 = 180 liters.
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