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    Question

    A mixture (cola + water) contains cola and water in the

    ratio of 3:2. If 40 liters of the mixture is replaced with 10 liters of water, then the quantity of cola in the final mixture becomes 18 liters more than that of water. Find the initial quantity of the mixture.
    A 249 Correct Answer Incorrect Answer
    B 150 Correct Answer Incorrect Answer
    C 165 Correct Answer Incorrect Answer
    D 180 Correct Answer Incorrect Answer
    E none of these Correct Answer Incorrect Answer

    Solution

    ATQ, Let the quantity of cola and water in the initial mixture be '3u' liters and '2u' liters, respectively. Quantity of cola in 40 liters of the mixture = 40 x (3/5) = 24 liters. Quantity of water in 40 liters of the mixture = 40 - 24 = 16 liters. According to the question, (3u - 24) = (2u - 16 + 10) + 18 Or, 3u - 2u = 24 - 16 + 10 + 18 Or, u = 36 Initial quantity of the mixture = 5u = 5 x 36 = 180 liters.

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