A container has 120 liters of milk and 'x' liters of water. If 25% of the mixture is removed and then 10 liters of water are added such that the quantities of milk and water become equal in the final mixture, what is the value of 'x'? (Calculate approximate value)
ATQ, Original amounts: Milk = 120 liters Water = x liters 25% removed: Milk removed = 0.25 × 120 = 30 liters Water removed = 0.25 × x = 0.25x liters Remaining: Milk remaining = 120 - 30 = 90 liters Water remaining = x - 0.25x = 0.75x liters Adding water: Final water = 0.75x + 10 liters Equal amounts: 90 = 0.75x + 10 Solving for 'x': 0.75x = 90 - 10 0.75x = 80 x = 80 / 0.75 ≈ 106.67 liters or 107 liters
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