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We have -2 π h (R-r) = 132 = 2×22/7×21(R-r) =132 R-r = 1 Also given – R + r = 21 Then – R = 11cm, r = 10cm. So, the total surface of the hollow cylinder = 2 π h(R-r) +2 π (R2-r2) =2 π (R +r) [h +R-r] =2×22/7×21(21+1) =6×22×22 =2904cm2
(33 + 6.25% of 4096) = ? + 2 × 119
345 × 20 ÷ 4 + 28 + 60 = ?
236.23 - 653.23 + 696.23 = ?
1220 ÷ 61 ÷ 5 + 450 of 20% - 70 = √ ?
(64 × 16) ÷ (4 × 16) 3 × 256 2 = 4 ?
25% of 440 + 88 X (1/2)2 - 28 = 8 X ?
(6.013 – 20.04) = ? + 9.98% of 5399.98
The value of 3 × 7 + 5 – 6 ÷ 3 – 9 + 45 ÷ 5 × 4 – 45 is: