Question
A container holds 640 litres of a solution of milk and
water in the ratio 3:5. If (x + 20) litres of water is added, the new ratio of milk to water becomes 3:7. What is the value of x?Solution
ATQ,
Quantity of milk initially in container = (3/8) × 640 = 240 litres Quantity of water initially in container = (5/8) × 640 = 400 litres According to question, 240 / [400 + (x + 20)] = 3 / 7 ⇒ 240 × 7 = 3 × (420 + x) ⇒ 1680 = 3 × (420 + x) ⇒ 1680 = 1260 + 3x ⇒ 3x = 420 ⇒ x = 140
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