Question
40 litres of a solution contains 20% milk. After adding
'd' litres of pure milk, the quantity of milk becomes 150% more than the quantity of water. If milk costs Rs. 30 per litre, what is the total selling price of the resulting mixture if it is sold at the milk's cost price per litre?Solution
ATQ, Quantity of milk in 40 litres of mixture = 40 Γ 0.20 = 8 litres Quantity of water in 40 litres of mixture = 40 - 8 = 32 litres Final quantity of milk after adding 'd' litres = (8 + d) litres A.T.Q. (8 + d)/32 = 5/2 β 8 + d = 80 β d = 72 litres Total quantity of mixture = 40 + 72 = 112 litres Total selling price of final mixture = 112 Γ 30 = Rs. 3360
Β If 4x = 40, 3y = 33, what is the value of 6x + 4y?
I. 2yΒ² - 3y β 14 = 0
II. 3xΒ² - 7x + 4 = 0
If a quadratic polynomial y = ax2 + bx + c intersects x axis at a and Ξ², then
I. 7x + 8y = 36
II. 3x + 4y = 14
I. 4p² + 17p + 15 = 0
II. 3q² + 19q + 28 = 0
The equation x2 β px β 60 = 0, has two roots βaβ and βbβ such that (a β b) = 17 and p > 0. If a series starts with βpβ such...
I. x2 + 16x + 63 = 0
II. y2 + 2y - 15 = 0
I. 40 x² - 93 x + 54 = 0
II. 30 y² - 61 y + 30 = 0
I. x + 1 = 3β 9261
II. y + 1 = β 324
I. 35x² - 24x – 35 = 0
II. 72y² - 145y + 72 = 0
Relevant for Exams:
