Question
40 litres of a solution contains 20% milk. After adding
'd' litres of pure milk, the quantity of milk becomes 150% more than the quantity of water. If milk costs Rs. 30 per litre, what is the total selling price of the resulting mixture if it is sold at the milk's cost price per litre?Solution
ATQ, Quantity of milk in 40 litres of mixture = 40 × 0.20 = 8 litres Quantity of water in 40 litres of mixture = 40 - 8 = 32 litres Final quantity of milk after adding 'd' litres = (8 + d) litres A.T.Q. (8 + d)/32 = 5/2 ⇒ 8 + d = 80 ⇒ d = 72 litres Total quantity of mixture = 40 + 72 = 112 litres Total selling price of final mixture = 112 × 30 = Rs. 3360
l). 3p + 2q = 27
ll). 4p - 3q = 2
- Find the value of p if the quadratic equation x² + px + 36 = 0 has real and equal roots.
What will be the product of smaller roots of both equations.Â
In the question, two equations I and II are given. You have to solve both the equations to establish the correct relation between 'p' and 'q' and choose...
Solve the quadratic equations and determine the relation between x and y:
Equation 1: 4x² - 12x + 9 = 0
Equation 2: 2y² + 8y + 6 = 0
I. 63x2 + 148x + 77 = 0
II. 21y2 + 89y + 88 = 0
I. 8y2 - 2y - 21 = 0
II. 2x2 + x - 6 = 0
I. x2 – 13x + 36 = 0
II. 3y2 – 29y + 18 = 0
If ‘y1’ and ‘y2’ are the roots of quadratic equation 5y2 – 25y + 15 = 0, then find the quadratic equation whose roots are ‘3y1�...
I. 144x² - 163x - 65 = 0
II. 91y² - 128y -48 = 0
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