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ATQ,
Let amount of wine and water in the original mixture be 5x ml and 6x ml respectively.
Amount of wine in 132 ml of mixture = 5/11 × 132 = 60 ml
Amount of water in 132 ml of mixture = 132 – 60 = 72 ml
According to the question:
(6x – 72 + 264) = 2 × (5x – 60)
Or, 6x + 192 = 10x – 120
Or, 4x = 312
Or, x = 78
Original quantity of mixture = 11x = 11 × 78 = 858 ml
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