Question
The length and breadth of a rectangular field are 51m
and 30m respectively. A tank of length 8m, breadth 7m and depth 5m is dug out at the middle of the field. The earth removed is evenly spread over the remaining part of the field. Find the approximate rise in the level of the remaining part of the field?Solution
Volume of the earth dug out = 8Ć7 Ć5 = 280 mĀ³ The upper surface area of the field = 8Ć7 = 56 mĀ² Total surface area of the field = 51Ć30 = 1530 mĀ²Ā Remaining area of the field = (1530 ā 56) = 1474 mĀ² ā“ Rise in the level of the remaining part of the field = 280/1474m = (28/1474) Ć 100cm= 18.99 cm ā¼19cm
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