New Click here to Enroll for SIDBI MSME Expert Classes by Experts

    Register

    Question

    The length and breadth of a rectangular field are 51m

    and 30m respectively. A tank of length 8m, breadth 7m and depth 5m is dug out at the middle of the field. The earth removed is evenly spread over the remaining part of the field. Find the approximate rise in the level of the remaining part of the field?
    A 19 cm Correct Answer Incorrect Answer
    B 32.4 cm Correct Answer Incorrect Answer
    C 26.4 cm Correct Answer Incorrect Answer
    D 12.4 cm Correct Answer Incorrect Answer

    Solution

    Volume of the earth dug out = 8×7 ×5 = 280 m³ The upper surface area of the field = 8×7 = 56 m² Total surface area of the field = 51×30 = 1530 m²  Remaining area of the field = (1530 – 56) = 1474 m² ∴ Rise in the level of the remaining part of the field = 280/1474m = (28/1474) × 100cm= 18.99 cm ∼19cm

    Practice Next

    Relevant for Exams: