Question
The angle of depression of a point on the ground as seen from the top of a tower, 25 feet high, is 45°. Find the distance of the point on the ground from the foot of the tower.
More Height and Distance Questions
- There is a fire in the building. A man on the top of the building see a Fire brigade van coming towards it. If it takes 8 minutes for the angle of depressi...
- Now a chord of a circle is such that AB = 10 cm. If the diameter of the circle is 20 cm, then the angle subtended by the chord at the center is.
- A tree of height 'h' meters is partially bent at a certain point above the ground, causing its top to touch the ground at a distance of 12 meters from its ...
- Find the area of maximum side of square that can be inscribed in a right angled triangle of side 15, 20 and 25 cm.
- There are two houses of the same height on both sides of a 30-meter wide road. From a point on the road, elevation angles of the houses are 30° and 60&...
- The angle of elevation of an aeroplane from a point on the ground is 60°. After 12 seconds flight the elevation changes to 30°, if the aeroplane is...
- From the top of a tower, the angle of depression of a car on the ground is 30°. After the car moves 40 m towards the tower in a straight line, the angle of...
- From a point on the ground, the angle of elevation of the top of a tower is 30 degrees. After moving 10√3 m towards the tower, the angle becomes 60 degrees...
- There are two houses of the same height on both sides of a 15-meter wide road. From a point on the road, elevation angles of the houses are 30° and 60° res...
- From a watch tower of 205 m height, the angles of depression of two cliffs in a horizontal line through the base of the tower are 45° and 30°. Find the dis...
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Let θ be the angle of depression of the point on the ground as seen from the top of a tower, here θ = 45° Let AC be the height of the tower, here AC = 25 feet. Let the distance of the point on the ground from the foot of the tower, AB = x feet. Here, tan θ = AC/AB ⇒ tan 45° = 25/x ⇒ 1 = 25/x ⇒ x = 25 feet