Question
The angle of depression of a point on the ground as seen from the top of a tower, 25 feet high, is 45°. Find the distance of the point on the ground from the foot of the tower.
More Height and Distance Questions
- Two men are on opposite sides of a tower of 75 m height. If they measure the elevation of the top of the tower as 30deg; and 45deg; respectively then the d...
- A Navy captain going away from a lighthouse at the speed of 4[(√3) – 1] m/s. He observes that it takes him 1 minute to change the angle of elev...
- From a point on the ground, the angle of elevation of the top of a tower is 30 degrees. After moving 10√3 m towards the tower, the angle becomes 60 degrees...
- At a point 20 metres away from the base of a 20√3, metres high house, the angle of elevation of the top is
- Two ships are on opposite sides in front of a lighthouse in such a way that all three of them are in line. The angles of depression of two ships from the t...
- The distance between two parallel poles is 65√3 m. The angle of depression of the top of the second pole when seen from the top of first pole is...
- The angle of elevation of the top of a building from a point on the ground is 30° and moving 40 meters towards the building it becomes 60°. The height of t...
- A shadow of a tower standing on level ground is found to be 40√3 meters longer when the Sun's altitude is 30° than when it is 60°. The height of the tower ...
- From a point on the ground, the angle of elevation of the top of a tower is 30°. After moving 20 m closer to the tower in a straight line, the angle of ele...
- A pole 6 m high casts a shadow 2√3 m long on the ground. Find the angle of elevation
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Let θ be the angle of depression of the point on the ground as seen from the top of a tower, here θ = 45° Let AC be the height of the tower, here AC = 25 feet. Let the distance of the point on the ground from the foot of the tower, AB = x feet. Here, tan θ = AC/AB ⇒ tan 45° = 25/x ⇒ 1 = 25/x ⇒ x = 25 feet