Question
The angle of depression of a point on the ground as seen from the top of a tower, 25 feet high, is 45°. Find the distance of the point on the ground from the foot of the tower.
More Height and Distance Questions
- In the village of Hazelton, there was a totem pole 50 m high of which the lower 24 m was carved. According to a clue the treasure was hidden at a point on ...
- Raju is positioned 30 meters away from the base of a tower. From his standing point, the angle of elevation to the top of the tower is 45°. Determine the h...
- The angle of depression from the top of a light-house of two boats are 60° and 30° towards the west, if the two boats are 60m apart, then the height of the...
- There are two houses of the same height on both sides of a 40-meter wide road. From a point on the road, elevation angles of the houses are 30° and 60° res...
- A vertical pole and a vertical tower are standing on the same level ground. Height of the pole is 15 metres . From the top of the pole the angle of elevati...
- A pole 9√3 m high casts a shadow 27 m long on the ground. Find the angle of elevation
- A man 3 m tall is 19 m away from a tower 22 m high. Determine the angle of elevation of the top of the tower from the eye of the observer.
- A pole 21 m high casts a shadow 7√3 m long on the ground. Find the angle of elevation
- From a point on the ground, the angle of elevation of the top of a tower is 30 degrees. After moving 10√3 m towards the tower, the angle becomes 60 degrees...
- A pole 6 m high casts a shadow 2√3 m long on the ground. Find the angle of elevation
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)
Let θ be the angle of depression of the point on the ground as seen from the top of a tower, here θ = 45° Let AC be the height of the tower, here AC = 25 feet. Let the distance of the point on the ground from the foot of the tower, AB = x feet. Here, tan θ = AC/AB ⇒ tan 45° = 25/x ⇒ 1 = 25/x ⇒ x = 25 feet