Question
From a point on the ground, the angle of elevation of
the top of a tower is 30 degrees. After moving 10β3 m towards the tower, the angle becomes 60 degrees. The height of the tower is:Solution
Let the nearer distance from tower be x m. Height = x tan 60 = xβ3 From the farther point: distance = x + 10β3 Height = (x + 10β3) tan 30 = (x + 10β3)/β3 So, xβ3 = (x + 10β3)/β3 3x = x + 10β3 2x = 10β3 x = 5β3 Height = xβ3 = 5β3 x β3 = 15
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