Question
The angle of elevation of the top of a building from a
point on the ground is 30° and moving 40 meters towards the building it becomes 60°. The height of the building is?Solution
Let AB bee the height of the building. In ∆ACD and ∆ABC ∠ACB = ∠CAD + ∠CDA 60° = ∠CAD + 30° ∠CAD = 30° So, AC = CD AC = 40 m cosec 60° = AC/AB 2/√3 = 40/AB AB = 20√3
More Height and Distance Questions
- Which letter-cluster will replace the question mark (?) in the following series?
RGV, UME, ?, AYW, DEF - Which letter-cluster will replace the question mark (?) in the following series?
NPQR, OORQ, PNSP, ____, RLUN - Select the number from among the given options that can replace the question mark (?) in the following series.
17, 18, 22, 31, 47, ___ - Which letter and number cluster will replace the question mark (?) to complete the given series?
LT6, KU12, IW24, FZ48, ____ - A series is given with one term missing. Choose the correct alternatives from the given ones that will complete the series.
57, 59, 56, 61, 54, ___
Relevant for Exams:
