Question
The angle of elevation of the top of a building from a point on the ground is 30° and moving 40 meters towards the building it becomes 60°. The height of the building is?
More Height and Distance Questions
- From a point on the ground, the angle of elevation of the top of a tower is 30 degrees. After moving 10√3 m towards the tower, the angle becomes 60 degrees...
- The angle of elevation of a tower from a certain point of bus stand is 30°. When a man walks 5m ahead in the direction of the tower, the angle of elevatio...
- From a point situated at some distance from the base of a pillar, the angle of elevation of the top of the pillar is found to be 45 degrees. After walking ...
- A pole 9√3 m high casts a shadow 27 m long on the ground. Find the angle of elevation
- From a point on the ground, the angle of elevation of the top of a tower is 30 degrees. After moving 20 m towards the tower, the angle becomes 60 degrees. ...
- The distance between two parallel poles is 65√3 m. The angle of depression of the top of the second pole when seen from the top of first pole is 30°. What ...
- There is a fire in the building. A man on the top of the building see a Fire brigade van coming towards it. If it takes 8 minutes for the angle of depressi...
- The distance between two parallel poles is 65√3 m. The angle of depression of the top of the second pole when seen from the top of first pole is 30o. What ...
- The angle of depression of a point on the ground as seen from the top of a tower, 65 feet high, is 45°. Find the distance of the point on the ground from t...
- Two buildings are collinear with the base of a tower and are at a distance 9m and 16m from the base of the tower. The angles of elevation from these two bu...
Relevant for Exams:
Hey! Ask a query
Please enter email id
The email must be a valid email address.
Please enter Mobile Number
Please enter valid Mobile Number
Please enter your Doubt
Think You're Ready for RBI Grade B?
RBI Grade B 2026 Phase 1 Memory Based Paper
- 200 Questions with Detailed Solutions
- Section-wise Coverage (GA, English, Quant & Reasoning)
Let AB bee the height of the building. In ∆ACD and ∆ABC ∠ACB = ∠CAD + ∠CDA 60° = ∠CAD + 30° ∠CAD = 30° So, AC = CD AC = 40 m cosec 60° = AC/AB 2/√3 = 40/AB AB = 20√3