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Start learning 50% faster. Sign in now Let the height of the tower be h And ∠CBD = θ and ∠ DAC = 90 – θ In ∆ BCD tan θ = CD/BC = h/9 …………(i) In ∆ ACD tan(90 - θ) = CD/AC cot θ = h/16 ……………………….(ii) On multiplying Equation (i) and (ii) tan θ × cot θ = h/9 × h/16 1 = h²/144 Now h = 12 m
18, 25, 33, 42, 52, 63, ?
(12% of 1250 + 85% of 400) x 10 = ?2
9999² + 1111² =?
1240 ÷ ? = 242 + 123 – 514 × 4
18 × √225 + 378 ÷ √441 = ? × 9
(190/38) × (55/5) + (306/18) = ?
1024 ÷ 32 = 2(1/2)×?
125% of 129 ÷ 43 × 28 ÷ 7 = ? ÷ √16