Question
Find the area of maximum side of square that can be
inscribed in a right angled triangle of side 15, 20 and 25 cm.Solution
Let the side of the square be a Then, AD = 15 – a and FC = 20 - a Area of Triangle ABC = 1/2 × Base × Height = 1/2 × 15 ×20 = 150 cm² Now, Area of Triangles ADE and EFC + Area of Square BDEF = Area of Triangle ABC ∴ 1/2 ×a × (15 - a) + 1/2 × a × (20 - a) + a² = 150 15a/2 - a²/2 + 10a - a²/2 + a² = 150 (15a+20a)/2 = 150 35a = 300 a = 300/35 = 60/7 cm Area of Square = 3600/49 cm²
31.98% of 224.99 = 24.98% of ? + 9.91% of 499.99
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exactvalue.)
49.99% of 639.99 + 159.98% of 49.99 = ?2
79.79% of 299.87 - 54.67% of (39.982 - 9.822 ) = ? - 19.92 × 199.98
? + 144.99 – 110.01 = 15.01 × 7.98
24.89% of 720.01 - 4.09 × ? = (5.89)2
45.1298% of (14.032 - 75.98) + 27.87% of √40001 = 449.98% of 24.098 + ?Â
- What approximate value will come in place of the question mark (?) in the following question? (Note: You are not expected to calculate the exact value.)
What approximate value will come in place of question (?) in the following given expression? You are not expected to calculate the exact value.
...1279.908 + 1499.897 ÷ 29.912 × 22.22 = ? + 82.210 × 4.908
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