Question
From the top of a tower, the angle of depression of a
car on the ground is 30Β°. After the car moves 40 m towards the tower in a straight line, the angle of depression becomes 45Β°. Find the height of the tower.Solution
Let the height of the tower be h m. Let the initial horizontal distance of the car from the tower be x m. Angle of depression = angle of elevation.a Initially: tan 30Β° = h/x So, 1/β3 = h/x β x = hβ3 ...(1) After moving 40 m towards tower, distance = x β 40. Now: tan 45Β° = h/(x β 40) So, 1 = h/(x β 40) β x β 40 = h ...(2) From (1) and (2): hβ3 β 40 = h h(β3 β 1) = 40 h = 40/(β3 β 1) = 40(β3 + 1)/( (β3 β 1)(β3 + 1) ) = 40(β3 + 1)/2 = 20(β3 + 1)
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